2x(5+x)-2=6(x-2)+2x^2

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Solution for 2x(5+x)-2=6(x-2)+2x^2 equation: 



2x(5+x)-2=6(x-2)+2x^2

We move all terms to the left:

2x(5+x)-2-(6(x-2)+2x^2)=0

We add all the numbers together, and all the variables

-(6(x-2)+2x^2)+2x(x+5)-2=0

We multiply parentheses

-(6(x-2)+2x^2)+2x^2+10x-2=0



We calculate terms in parentheses: -(6(x-2)+2x^2), so:

6(x-2)+2x^2

determiningTheFunctionDomain
2x^2+6(x-2)

We multiply parentheses

2x^2+6x-12

Back to the equation:

-(2x^2+6x-12)



We add all the numbers together, and all the variables

2x^2+10x-(2x^2+6x-12)-2=0

We get rid of parentheses

2x^2-2x^2+10x-6x+12-2=0

We add all the numbers together, and all the variables

4x+10=0

We move all terms containing x to the left, all other terms to the right

4x=-10

x=-10/4

x=-2+1/2

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